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1500=200x-5x^2
We move all terms to the left:
1500-(200x-5x^2)=0
We get rid of parentheses
5x^2-200x+1500=0
a = 5; b = -200; c = +1500;
Δ = b2-4ac
Δ = -2002-4·5·1500
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-100}{2*5}=\frac{100}{10} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+100}{2*5}=\frac{300}{10} =30 $
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